Câu 86 trang 25 Sách Bài Tập (SBT) Toán Lớp 6 tập 2

Tính:

a) \({\rm{}}{2 \over 3} + {1 \over 5}.{{10} \over 7}\)

b) \({7 \over {12}} - {{27} \over 1}.{1 \over {18}}\)

c) \(\left( {{{23} \over {41}} - {{15} \over {82}}} \right).{{41} \over {25}}\)

d) \({\rm{}}\left( {{4 \over 5} + {1 \over 2}} \right).\left( {{3 \over {13}} - {8 \over {13}}} \right)\)

Giải

a) \({\rm{}}{2 \over 3} + {1 \over 5}.{{10} \over 7} \)

\(= {2 \over 3} + {{1.10} \over {5.7}} \)

\(= {2 \over 3} + {2 \over 7} \)

\(= {{14} \over {21}} + {6 \over {21}}\)

\(= {{20} \over {21}}\) 

b) \({7 \over {12}} - {{27} \over 1}.{1 \over {18}} \)

\(= {7 \over 2} - {{27.1} \over {7.18}} \)

\(= {7 \over 2} - {3 \over {14}} \)

\(= {{49} \over {14}} + {{ - 3} \over {14}} \)

\(= {{46} \over {14}} = {{23} \over 7}\) 

c) \(\left( {{{23} \over {41}} - {{15} \over {82}}} \right).{{41} \over {25}} \)

\(= \left( {{{46} \over {82}} + {{ - 15} \over {82}}} \right).{{41} \over {25}} \)

\(= {{31} \over {82}}.{{41} \over {25}} \)

\(= {{31.41} \over {82.25}} = {{31} \over {50}}\) 

d) \({\rm{}}\left( {{4 \over 5} + {1 \over 2}} \right).\left( {{3 \over {13}} - {8 \over {13}}} \right) \)

\(= \left( {{8 \over {10}} + {5 \over {10}}} \right).\left( {{3 \over {13}} + {{ - 8} \over {13}}} \right)\)

\(= {{13} \over {10}}.{{ - 5} \over {13}} = {{13.( - 5)} \over {10.13}} = {{ - 1} \over 2}\) 

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